wrightsc9707 wrightsc9707

07-05-2018
Mathematics

contestada

Part A: Factor 5x2b2 + 14xb2 − 3b2. Show your work.
Part B: Factor x2 − 18x + 81. Show your work.
Part C: Factor x2 − 121. Show your work.

Respuesta :

carlosego carlosego

16-05-2018

Part A:
We have the following expression:
5x2b2 + 14xb2 - 3b2
Rewriting we have:
b2 (5x2 + 14x - 3)
b2 (5x-1) (x + 3)

Part B:
We have the following expression:
x2 - 18x + 81
Rewriting we have:
(x-9) (x-9)
(x-9) ^ 2

Part C:
We have the following expression:
x2 - 121
Rewriting we have:
(x-11) (x + 11)

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