lexivaldez2319
lexivaldez2319
07-05-2018
Mathematics
contestada
Factor completely 2x^3+6x^2+2x+6
Respuesta :
choixongdong
choixongdong
07-05-2018
2x^3+6x^2+2x+6
= 2(
x^3 + 3x^2 + x + 3)
= 2[x^2 (x + 3) + (x + 3)]
= 2(x^2 + 1)(x + 3)
hope it helps
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Аноним
Аноним
07-05-2018
f(-3) = 2*-27 + 6*9 + 2*-3 + 6 = 0
so x + 3 is a factor
dividing the function by x + 3 gives the quotient
2x^2 + 2 = 2 (x^2 + 1)
So the factors are 2(x^2 + 1)(x + 3) Answer
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