shockwavegaming9
shockwavegaming9
10-07-2018
Mathematics
contestada
Still pretty confused on this.
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konrad509
konrad509
10-07-2018
[tex]\displaystyle \sum_{i=3}^7(3i-1)=3\cdot3-1+3\cdot4-1+3\cdot5-1+\\\\ +3\cdot6-1+3\cdot7-1=8+11+14+17+20=70[/tex]
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