Jerry is experimenting with chemicals in the laboratory. He mixes a solution that is 10% acid with a solution that is 30% acid. How much of the 10% acid solution will be needed to make 40 liters of a solution that is 25% acid?
The formula: [tex]\hbox{volume percent} = \frac{\hbox{volume of solute}}{\hbox{volume of solution}} \cdot 100\%[/tex]
Data: [tex]\hbox{volume percent}_1 =10\% \\
\hbox{volume of solution}_1= x \\
\hbox{volume of solute}_1 = 10\% x=0.1x \\ \\
\hbox{volume percent}_2 =30\% \\
\hbox{volume of solution}_2= y \\
\hbox{volume of solute}_2 = 30\% y=0.3x \\ \\ \hbox{volume percent}_3 =25\% \\ \hbox{volume of solution}_3= 40 \ l \\ \hbox{volume of solute}_1 = 25\% \cdot 40 \ l =10 \ l \\[/tex]
You need to make 40 l of a solution with 10 l of solute. [tex]\hbox{volume of solute}_1+ \hbox{volume of solute}_2 = 10 \ l \\
\hbox{volume of solution}_1 + \hbox{volume of solution}_2= 40 \ l[/tex]
