Respuesta :

gmany

[tex]\dfrac{3}{4}x+5-\dfrac{1}{2}x=3\qquad|\text{multiply both sides by 4}\\\\\not4^1\cdot\dfrac{3}{\not4_1}x+4\cdot5-\not4^2\cdot\dfrac{1}{\not2_1}x=4\cdot3\\\\3x+20-2x=12\\\\(3x-2x)+20=12\qquad|\text{subtract 20 from both sides}\\\\x=-8[/tex]

Answer: A. -8

abgallegos30
A= -8 is the answer because you subtract five from both sides the subtract 3/4 and 1/2 to get 1/4. The divide -2 by 1/4 to get the answer x= -8