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The gas inside a large engine cylinder initially has a pressure of 105 kilopascals and a volume of 2.031 liters. If the gas is compressed at constant temperature to a volume of 0.356 liter, what is its new pressure? The pressure of the compressed gas is________ kilopascals. just fill in the blank thank u

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kenmyna

The  new  pressure  of the compressed  gas is 599 kilopascals

    calculation

This is calculate using  Boyle's  law  formula

That is P₁V₁ =P₂V₂

where;

P₁ = 105 kilopascals

V₁ = 2.031 L

P₂ = ?  kilopascals

V₂ =0.356 L

make P₂ the subject of the formula  by diving both side of equation by V₂

P₂ = P₁V₁/V₂

P₂ = {(105 kilopascals  x 2.031 L)/0.356 L} = 599 kilopascals

The pressure of the compressed gas is 599 kilopascals.

How we calculate the pressure by using ideal gas equation?

We can calculate the pressure of gas by using the ideal gas equation as:

P₁V₁ = P₂V₂, where

P₁ = initial pressure of gas = 105 kilopascals

V₁ = initial volume of gas = 2.031 L

P₂ = to find?

V₂ = compressed volume of gas = 0.356 L

We do not consider temperature here because temperature is constant for the given question.

On putting all these values in the above equation, we get

P₂ = (105 × 2.031) / 0.356 = 599 kilopascals

Hence, 599 kilopascals is its new pressure.

To know more about ideal gas equation, visit the below link:

https://brainly.com/question/20348074

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