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f as a function of x is equal to the square root of quantity 6 x plus 9 , f as a function of x is equal to the square root of quantity 6 x minus 9

Find (f + g)(x). (5 points)

f as a function of x is equal to the square root of quantity 6 x plus 9 f as a function of x is equal to the square root of quantity 6 x minus 9 Find f gx 5 poi class=

Respuesta :

Answer:

A. [tex]\sqrt{6x+9} +\sqrt{6x-9}[/tex]

Step-by-step explanation:

We are given the functions f(x) and g(x) as,

[tex]f(x)=\sqrt{6x+9}[/tex]

[tex]g(x)=\sqrt{6x-9}[/tex]

It is required to find the function ( f+g ) i.e. ( f+g ) (x)

So, [tex](f+g)(x)=f(x)+g(x)[/tex]

i.e. [tex](f+g)(x)=\sqrt{6x+9}+\sqrt{6x-9}[/tex]

Hence, we get that [tex](f+g)(x)=\sqrt{6x+9}+\sqrt{6x-9}[/tex].

So, the first option is correct.