electronia electronia

09-01-2019
Chemistry

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What is the mole ratio of lead nitrate to potassium iodide in the following reaction?
https://lh5.googleusercontent.com/wcEhfSZoHDJT_UFoJFG5Sy05FSSIhZHOAc2ShwBJGQVnOjodXUJewhr8tbfy-1XVXzxEHUIp0w=w306

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superman1987 superman1987

20-01-2019

Answer: 1:2.

Explanation:

It is a stichiometric problem,

from the equation: Pb(NO₃)₂ + 2KI → PbI₂ + 2KNO₃

The stichiometry of this reaction shows that 1.0 mol of lead nitrate reacts with 2.0 moles of KI to produce 1.0 mole of lead iodide and 2.0 moles of potassium nitrate.

Thus, the mole ratio of lead nitrate to potassium iodide is 1:2.

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