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In partial fraction decomposition, if you have a square factored term in the denominator, for instance [tex]\frac{x+3}{(x+7)(x-5)^{2} }[/tex] why do you use two different terms when making the partial fractions with one for, in this instance, (x-5) and [tex](x-5)^{2}[/tex]

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PeachyLove

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âž· This is because the partial fraction needs to be added to the square version in order to get the final answer.

Using the example in the question:

You have to create the partial fraction template

(I will just show the denominator part to help you understand)

(x + 7) + (x - 5) + (x - 5)^2

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