A plane takes off at an angle of elevation of 15° and travels in a straight line for 3,000 meters. What is the height of the plane above the ground at this instant? A. 2898 m B. 2701 m C. 804 m D. 776 m

Respuesta :

Answer:

D 776 m.

Step-by-step explanation:

Use trigonometry. The line of flight of the plane, it's height above the ground and the  distance travelled along the ground form a right angled triangle.

So sin 15 = opposite side   / hypotenuse.

sin 15 = h / 3000  where h = its height..

h = 3000 sin 15

=  776 m.