Answer:
[tex] ^ 9 C _ 3 ( 0 . 5 ) ^ 3 ( 0 . 5 ) ^ 6 [/tex]
Step-by-step explanation:
We know that Aron flips a penny 9 times and gets exactly 3 heads .
Probability of getting a head or a tail is [tex] \frac { 1 } { 2 } [/tex].
Here, we need to find the probability of getting exactly 3 heads:
[tex]P(x=3)=^9C_3(\frac{1}{2})^3\times \frac{1}{2}^6\\\\P(x=3)=^9C_3(0.5)^3\times (0.5)^6\\\\P(x=3)=\frac{9!}{3!\tiems 6!}\times (0.5)^9\\\\P(x=3)=0.16[/tex]
So the expression representing this situation will be:
[tex] ^ 9 C _ 3 ( 0 . 5 ) ^ 3 ( 0 . 5 ) ^ 6 [/tex]
