The mass flow rate in a 4.0-m wide, 2.0-m deep channel is 4000 kg/s of water. If the velocity distribution in the channel is linear with depth what is the surface velocity of flow in the channel?

Respuesta :

Answer:

V = 0.5 m/s

Explanation:

given data:

width of channel =  4 m

depth of channel = 2 m

mass flow rate = 4000 kg/s = 4 m3/s

we know that mass flow rate is given as

[tex]\dot{m}=\rho AV[/tex]

Putting all the value to get the velocity of the flow

[tex]\frac{\dot{m}}{\rho A} = V[/tex]

[tex]V = \frac{4000}{1000*4*2}[/tex]

V = 0.5 m/s