If h(x) = 3x − 1 and j(x) = −2x, solve h[j(2)] and select the correct answer below.
−11
11
−13
13

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Respuesta :

meerkat18 meerkat18 · Answer 1 · 2016-05-18T22:04:52+02:00

h(x) = 3x - 1
j(x) = -2x

h[j(2)] ⇒ j(2) = -2(2) ⇒ j(2) = -4

h(-4) = 3(-4) - 1
h(-4) = -12 - 1
h(-4) = -13

h[j(2)] = -13

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OrethaWilkison OrethaWilkison · Answer 2 · 2019-02-25T08:21:37+01:00

Answer:

Option 3rd is correct.

the value of h[j(2)] is, -13

Step-by-step explanation:

Given the functions:

[tex]h(x) = 3x-1[/tex]

[tex]j(x) = -2x[/tex]

We have to find the value of h[j(2)]

[tex]h[j(x)] = h[-2x][/tex]

Replace x from -2x in h(x) we have;

[tex]h[-2x] = 3(-2x)-1 = -6x -1[/tex]

⇒[tex]h[j(x)] = -6x-1[/tex]

Substitute the value of x = 2 we get;

[tex]h[j(2)] = -6(2)-1 = -12-1 = -13[/tex]

Therefore, the value of h[j(2)] is, -13