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Calculate the amount of heat (in kilojoules) required to vaporize 2.60 kg of water at its boiling point. (?Hvap=40.7 kJ/mol at 100?C.) Express your answer to three significant figures and include the appropriate units.

Respuesta :

Answer:

heat require for vaporize = 5873.98 kJ

Step-by-step explanation:

Given data

mass of water = 2.60 kg

Hvap = 40.7 kJ/mol

to find out

Calculate the amount of heat

solution

we know heat required for 1 mol of water to vaporize at 100 degree c is 40.7 kg

and

we know water weight of 1 mol is  18.015 gram

so mole of 2.60 kg water is  = 2600 / 18.1015

that is = 144.3241 mol

so heat require for vaporize 144.3241 mol of water is = 144.3241 × 40.7

heat require for vaporize = 5873.98 kJ

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