Answer:
Distance, r = 10757.05 meters
Explanation:
Charge on two generic humans, q = 3 C
They have to be for the electric attraction between them to equal their 700 N weight, F = 700 N
Electric force is given by :
[tex]F=\dfrac{kq^2}{r^2}[/tex], r is the distance between charges
[tex]r=\sqrt{\dfrac{kq^2}{F}[/tex]
[tex]r=\sqrt{\dfrac{9\times 10^9\times 3^2}{700}}[/tex]
r = 10757.05 meter
So, distance between two charges is 10757.05 meters. Hence, this is the required solution.
