Respuesta :
Answer:
K.E = 463.04 k J
P = 23.14 Watt
Explanation:
given,
mass of automobile = 1200 kg
velocity = 50 km/h
       = 50 × 0.278
       = 13.9 m/s
kinetic energy = [tex]\dfrac{1}{2}mv^2[/tex]
            =[tex]\dfrac{1}{2}\times 1200 \times 13.9^2[/tex]
    K.E = 115.93 k J
vehicle accelerated to velocity = 100 km/h
                          = 100 × 0.2778
                          = 27.78 m/s
kinetic energy = [tex]\dfrac{1}{2}mv^2[/tex]
            =[tex]\dfrac{1}{2}\times 1200 \times 27.78^2[/tex]
    K.E = 463.04 k J
work done = change in kinetic energy
          = 463.04 - 115.93
          = 347.11 J
Power = [tex]\dfrac{work\ done}{time}[/tex]
Power =[tex]\dfrac{347.11}{15}[/tex]
P = 23.14 Watt
