Answer:
a)
1) event one:
do= ud[1/(u+v)]
2) event two:
d1= ud[(u-v)/(u+v)2]
3) event three:
d2= ud[(u-v)2/(u+v)3] Â
then:
       s=do+d1+d2+...
        = ud[1/(u+v)] + ud[(u-v)/(u+v)2] + ud[(u-v)2/(u+v)3] +...
       s= ud{[1/(u+v)] + [(u-v)/(u+v)2] + [(u-v)2/(u+v)3] + ...}
answer: Â s=ud{d/(2v)}
b) Meeting time between trains.
T= d/(V+V)=d/(2V)
distance traveled by the bee:
        s= T(u)
        s= d/(2V)(u)
answer: Â Â s= ud/(2v)