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2.00 mol of H2(g) and 1.00 mol of I2(g) are placed in a 1.00 L container, and they react to form HI(g). At equilibrium, it is found that 1.80 moles of HI(g) are present in the container. Calculate K for the reaction: H2(g) I2(g) ⇄ 2 HI(g)

Respuesta :

joseaaronlara

Answer:

The answer to your question is:         k = 1.62

Explanation:

Data

H2(g) = 2.00 mol

I2 (g) = 1.00 mol

HI (g) = 1.80 mol

K = ?

Reaction              H2(g)  +    I2(g)     ⇄     2 HI(g)

Formula

                       [tex]k = \frac{[[HI]^{2} }{[H2][I2]}[/tex]

Substitution

                             [tex]k = \frac{[1.8]^{2} }{[2][1]}[/tex]

                                    k = [tex]\frac{3.24}{2}[/tex]

                                    k = 1.62

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