Answer:
The value of the account will be $5,628
Step-by-step explanation:
we know that  Â
The compound interest formula is equal to Â
[tex]A=P(1+\frac{r}{n})^{nt}[/tex] Â
where Â
A is the Final Investment Value Â
P is the Principal amount of money to be invested Â
r is the rate of interest  in decimal
t is Number of Time Periods Â
n is the number of times interest is compounded per year
in this problem we have Â
[tex]t=21\ years\\ P=\$3,000\\ r=3\%=3/100=0.03\\n=12[/tex] Â
substitute in the formula above Â
[tex]A=3,000(1+\frac{0.03}{12})^{12*21}[/tex] Â
[tex]A=3,000(1.0025)^{252}[/tex] Â
[tex]A=\$5,628[/tex] Â
therefore
The value of the account will be $5,628