A conjecture and the flowchart proof used to prove the conjecture are shown.

Given: A B C D is a parallelogram. Prove: Angle 1 is supplementary to angle 3. Art: Parallelogram A B C D. Ray D B is drawn and is extended past vertex B. The ray forms an interior angles A D B and D B C and an exterior angle labeled as 3, adjacent to angle D B C. Angle A D B is labeled as 1, and angle D B C is labeled as 2.

Drag an expression or phrase to each box to complete the proof.

Question

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erinna erinna · Answer 1 · 2019-11-07T10:39:52+01:00

Answer:

∠1 is supplementary to ∠3.

Step-by-step explanation:

Given information: ABCD is a parallelogram.

Prove: ∠1 is supplementary to ∠3.

Proof:

∠1 = ∠ADB

∠2 = ∠DBC

∠3 = exterior angle adjacent to angle D B C.

Statement Reason

∠2 is supplementary to ∠3 Linear pairs

m∠2+m∠3=180° Definition of supplementary angles

[tex]m\angle 1=m\angle 2[/tex] Alternative interior angles

m∠1+m∠3=180° Substitute property of equality

∠1 is supplementary to ∠3 Definition of supplementary angles

Hence proved.

estes6146 estes6146 · Answer 2 · 2021-10-11T23:36:31+02:00

estes6146 estes6146

Answer:

my best answer would be 2

Step-by-step explanation:

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