contestada

an NHL hockey player (m=90 kg) stands motionless on the ice . the 10 kg stanley cup is thrown to the player at 4m/s. after he catches the cup determine the speed of the player cup combination. assuming there is no friction between the skates and the ice?

Respuesta :

Answer:v=0.4 m/s

Explanation:

Mass hockey player [tex]m_1=90 kg[/tex]

mass of  cup [tex]m_2=10 kg[/tex]

Velocity of cup [tex]u=4 m/s[/tex]

let v be the velocity of the combined system

Conserving momentum

[tex]m_1\cdot 0+m_2u=(m_1+m_2)v[/tex]

[tex]v=\frac{10\times 4}{100}[/tex]

[tex]v=\frac{40}{100}[/tex]

[tex]v=0.4 m/s[/tex]

Otras preguntas