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Computer-controlled display screens provide drivers in the Indianapolis 500 with a variety of information about how their cars are performing. For instance, as a car is going through a turn, a speed of 93.8 m/s and centripetal acceleration of 4.13 g (4.13 times the acceleration due to gravity) are displayed. Determine the radius of the turn (in meters).

Respuesta :

Answer:r=217.38 m/s

Explanation:

Given

Speed of car [tex]v=93.8 m/s[/tex]

Centripetal acceleration [tex]a_c=4.13 g[/tex]

During a turn centripetal acceleration is given by [tex]\frac{v^2}{r}[/tex]

[tex]a_c=\frac{v^2}{r}[/tex]

[tex]r=\frac{v^2}{a_c}[/tex]

[tex]r=\frac{93.8^2}{4.13g}[/tex]

[tex]r=\frac{93.8^2}{4.13\times 9.8}[/tex]

[tex]r=\frac{8798.44}{40.474}[/tex]

[tex]r=217.38 m[/tex]

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