Answer: 95% confidence interval would be (26.01,29.39).
Step-by-step explanation:
Since we have given that
n = 50
Mean = 27.7
Standard deviation = 6.12
We need to construct 95% confidence interval for the population.
so, z = 1.96
So, it becomes,
[tex]\bar{x}\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=27.7\pm 1.96\times \dfrac{6.12}{\sqrt{50}}\\\\=27.7 \pm 1.69\\\\=(27.7-1.69,27.7+1.69)\\\\=(26.01,29.39)[/tex]
Hence, 95% confidence interval would be (26.01,29.39).
