Answer:
Explanation:
Average power in AC is given as
[tex]P = i_{rms} V_{rms} cos\phi[/tex]
As we know that when AC is connected across the Resistor then we will have
[tex]cos\phi = 1[/tex]
now we have
[tex]P = \frac{i_oV_o}{2}[/tex]
here we have
[tex]V_o = NBA\omega[/tex]
[tex]V_o = 1260(0.830)(\pi\times 0.045^2)(2\pi \frac{3600}{60})[/tex]
[tex]V_o = 2508.15 Volts[/tex]
now we have
[tex]P = \frac{2508.15 \times 2508.15}{2 \times 20}[/tex]
[tex]P = 1.57 \times 10^5 Watt[/tex]
