Answer:
[tex]v_{water} = 1.325\ m/s[/tex]
Explanation:
given, Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
width of river = 76 m          Â
swimming at an angle = 28°        Â
constant rate of speed = 1.5 m/s    Â
rate at which river flow = ? Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
[tex]v_{water} = v_{max}\ cos \theta[/tex] Â Â Â Â Â Â Â Â Â
[tex]v_{water} = 1.5 \times\ cos 28^0[/tex] Â Â Â
[tex]v_{water} = 1.5 \times 0.883[/tex] Â Â Â Â Â Â
[tex]v_{water} = 1.325\ m/s[/tex] Â Â Â Â Â Â Â Â Â Â
hence, the rate of flow of river is equal to [tex]v_{water} = 1.325\ m/s[/tex]