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If you determine the molar heat of neutralization for an acid is 49.1 kJ/mol and the accepted value is found to be 55.2 kJ/mol, the what is the percent error in your answer?

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Answer: % Errror = 11.05%

Explanation:

Percentage error is the difference between the measured value and the theoretical value as expressed in percent.

That is;

% Error =

( Theoretical value -measured value) /(Theoretical value) × 100

Theoretical value =55.2kJ

Measured value = 49.1kJ

% Error = (55.2-49.1)/(55.2) ×100

%Error = 6.1/55.2 ×100

% Error = 0.1105 ×100

% Error = 11.05

Therefore the percentage error is 11.05%

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