Small rockets are used to make tiny adjustments in the speeds of satellites. One such rocket has a thrust of 35 N. If it is fired to change the velocity of a 72300 kg spacecraft by 60 cm/s, how long should it be fired?

Respuesta :

To solve this problem it is necessary to apply the concepts related to the Moment. The momentum represents the product of the mass and velocity of an object, that is

[tex]p = mv[/tex]

where

m = mass

v = velocity

At the same time using Newtonian relations, we can consider the Moment's equivalence as a function of Force and time as

p = Ft

Where

F = Force

t = time

Matching the two expressions we get that

[tex]mv = Ft[/tex]

Re-arrange to find t,

[tex]t = \frac{mv}{F}[/tex]

Our values are given as

[tex]m = 72300kg[/tex]

[tex]F = 35N[/tex]

[tex]v = 60cm/s(\frac{1m}{100cm})\rightarrow v = 0.6m/s[/tex]

Replacing we have that the time is

[tex]t = \frac{mv}{F}[/tex]

[tex]t = \frac{(72300)(0.6)}{35}[/tex]

[tex]t = 1239.4s[/tex]

Therefore would be take 1239.4s