Answer:
[tex]2.8\times10^{-8} Kgm^2[/tex]
Explanation:
Assuming that we have to calculate moment of inertia of balanced wheel about the shaft.
mass of balanced wheel = 0.80 g
radius of the rim = 0.53 cm
moment of inertia (I) = [tex]mr^2[/tex]
= [tex]0.85\times10^{-2}(\times0.58\times10^{-2})^2[/tex]
= [tex]2.8\times10^{-8} Kgm^2[/tex]
therefore, MOI of the wheel = [tex]2.8\times10^{-8} Kgm^2[/tex]
