Respuesta :
Answer:
A. 182.3 grams of HCl, are consumed.
B. The reaction produce 5 g of Hâ‚‚ and 238 g of MgClâ‚‚
Explanation:
This the balanced equation:
Mg (s)  + 2HCl (aq) →   MgCl₂(aq) + H₂(g)
Ratio between Mg and HCl is 1:2, so if I react 2.5 moles of Mg, I use the double of moles, of Hydrochloridric (5 moles)
Molar mass of HCl = 36.46 g/m
Mass = Moles . Molar mass
Mass = 5 m . 36.46 g/m →  182.3 g
In this case, we have no limiting reactant and nothing is in excess. It is the same for the calculations to do the rule of three.
1 mol of Mg makes 1 mol of MgClâ‚‚
2.5 moles of Mg makes 2.5 moles of MgClâ‚‚
2 mol of HCl makes 1 mol of MgClâ‚‚
5 moles of HCl makes 2.5 moles of MgClâ‚‚
In conlussion, this reaction makes 2.5 moles of MgClâ‚‚ and 2.5 moles of Hâ‚‚
Molar mass Hâ‚‚ = 2 g/m
Molar mass MgClâ‚‚ = 95.2 g/m
2.5 moles . 2 g/m = 5 g Hâ‚‚
2.5 moles . 95.2 g/m = 238 g MgClâ‚‚
A. The mass of HCl is consumed is 182.3 grams.
B. The  mass of each product is produced  is  5 g of H₂ and 238 g of MgCl₂
Calculation of the mass:
A.
We know that
The balanced equation is
Mg (s)  + 2HCl (aq) →   MgCl₂(aq) + H₂(g)
The ratio between Mg and HCl should be 1:2.
Due to this if I react 2.5 moles of Mg, So here I use the double of moles, of Hydrochloridric (5 moles)
So,
Molar mass of HCl = 36.46 g/m
Now
Mass = Moles . Molar mass
Mass = 5 m . 36.46 g/m →  182.3 g
B.
We know that
1 mol of Mg makes 1 mol of MgClâ‚‚
Likewise
2.5 moles of Mg makes 2.5 moles of MgClâ‚‚
2 mol of HCl makes 1 mol of MgClâ‚‚
5 moles of HCl makes 2.5 moles of MgClâ‚‚
Now
Molar mass Hâ‚‚ = 2 g/m
So,
Molar mass MgClâ‚‚ = 95.2 g/m
Now
2.5 moles . 2 g/m = 5 g Hâ‚‚
And,
2.5 moles . 95.2 g/m = 238 g MgClâ‚‚
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