Answer:
[tex]P =90\times 10^7\ W[/tex]
Explanation:
Given that
Volume flow rate ,Q= 1200 mĀ³ each Ā seconds
So we can say that
Q= 1200 mĀ³ /s
From energy conservation
(Potential energy +kinetic energy ) at top = (Potential energy +kinetic energy ) at bottom
Uā+ KEā = Uā+ KEā
Ļ Q g h + 0 = 0 + KEā
KEā= Ļ Q g h
For water ,Ļ Ā = 1000 kg/mĀ³
KEā=1000 x 1200 x 10 x 100 W Ā Ā Ā Ā Ā Ā ( take g= 10 m/sĀ²)
KEā=120 x 10ā· W
Only three forth of the energy converted into electrical energy
Therefore power P
[tex]P=\dfrac{3}{4}\times KE_2[/tex]
[tex]P=\dfrac{3}{4}\times 120\times 10^7\ W[/tex]
[tex]P =90\times 10^7\ W[/tex]
