Respuesta :
Answer:
100 kg
Step-by-step explanation:
Data provided in the question:
Initial total weight of the berries = 200 kg
Initial weight of water present = 99% of the weight
= 198 kg
therefore,
Initial weight of the solids in berries = 200 kg - 198 kg = 2 kg
After 2 days water was 98% of the total weight of the berries
Thus,
2% was solid which means 2 kg was 2% of the total weight of the berries
Thus,
2% of Total weight of berries after two days = 2 kg
or
0.02 × Total weight of berries after two days = 2 kg
or
Total weight of berries after two days = [ 2 ÷ 0.02 ] kg
or
Total weight of berries after two days = 100 kg
Answer:
100 kilograms!!!!
Step-by-step explanation:
First of all, let's find the variable and what it should represent.
Let's say m stands for the moisture in the berries.
Since the berries are 200 kg and the moisture in the berries is 99%, which is 198 kg. 2 kg remain, so we the left part of our equation will be :
m/(m+2).
The right part of our equation will be 0.98 because 0.98 is 98%, which is m.
m/(m+2)=0.98.
When we multiply m+2 on both sides, we get:
m=0.98m+1.96.
Subtracting 0.98m on both sides gives us 0.02m=1.96.
Dividing 0.02 on both sides gives us:
m=98.
The question is asking what is the total weight of the berries after two days, so we add 2 to 98, or 2+m, which is 100.
100 kilograms is the answer.
Hope this helped and thanks y'all!!!
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