Answer:
Rate of reaction is : 0.027 mol/Ls.
Explanation:
[tex]P_{4} + 5 O_{2} \rightarrow P_{4}O_{10}[/tex]
[tex]rate = +\frac{1}{1}\frac{\Delta [P_{4}O_{10}]}{\Delta t}[/tex]
[tex]{\Delta t} = 30 sec[/tex]
[tex]\Delta [P_{4}O_{10}] = 0.8[/tex]
[tex]rate = +\frac{1}{1}\frac{0.8}{30}[/tex]
rate = 0.027 mol/Ls
[tex]rate = 0.027 moleL^{-1}s^{-1}[/tex]
