contestada

two 1 MHz radio antennas emitting in-phase are separated by600
m along a north-south line. a radio reciever placed 2 kmeast is
equidistant from both transmitting antennas and picks up afairly
strong signal. How far north should that receiver bemoved if it is
again to detect a signal nearly as strong?

Respuesta :

boffeemadrid

Answer:

1 km

Explanation:

[tex]d_0[/tex] = Gap between antennas = 600 m

[tex]\nu[/tex] = Frequency = 1 MHz

[tex]z_1[/tex] = Distance to receiver = 2 km

c = Speed of light = [tex]3\times 10^8\ m/s[/tex]

Wavelength is given by

[tex]\lambda=\dfrac{c}{\nu}\\\Rightarrow \lambda=\dfrac{3\times 10^8}{1\times 10^6}\\\Rightarrow \lambda=300\ m[/tex]

Distance to be moved is given by

[tex]D=\dfrac{z_1\lambda_0}{d_0}\\\Rightarrow D=\dfrac{2\times 300}{600}\\\Rightarrow D=1\ km[/tex]

The distance to be moved is 1 km north.

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