Answer:
504 different prices can be formed using these cards.
Step-by-step explanation:
Different prices can be formed using these cards:
[tex]P^{n}_{k}=\frac{n!}{(n-k)!}[/tex]
where = n = number of cards
k = number of cards to be chose
n= 9, k = 3
[tex]P^{9}_{3}=\frac{9!}{(9-3)!}[/tex]
[tex]\frac{9\times 8\times 7\times 6!}{6!}=504[/tex]
504 different prices can be formed using these cards.
We calculated the number of permutations. We made this choice because in permutation order of element matters but in combination its not.
