Answer:
9.49 × 10⁶ m/s
Explanation:
Data provided in the question:
Magnitude of Magnetic force, F = 4.60 × 10⁻¹⁵ N
Angle, θ = 60°
Magnitude of magnetic field, B = 3.50 × 10⁻³ T
Now,
we know
F = qVBsin(θ)
here ,
q is the charge of electron = 1.6 × 10⁻¹⁹ V
V is the speed of electron
Therefore,
4.60 × 10⁻¹⁵ = ( 1.6 × 10⁻¹⁹ ) × V × ( 3.50 × 10⁻³ ) × sin(60°)
or
V = 9.49 × 10⁶ m/s
