Assuming A = dominant allele that produces red-eye, a = recessive allele that produces sepia eye, B = dominant allele that produces longwing, b = recessive allele that produces apterous wing. When crossing Aabb x AaBB, what is the probability of producing offspring with the sepia eye?

Respuesta :

Answer:

25% of probabilities

Step-by-step explanation:

A= red eye

a=sepia eye

B=longwing

b=apterous

         AB         aB

Ab     AABb     AaBb

ab      AaBb     aaBb

AABb=25%

AaBb=25%

Ab= 25%

aaBb=25%

aaBb= sepia eye with longwig