Answer:
fâ‚‚ = 0.019 m
Explanation:
Let's analyze this exercise a bit, when taking a picture the image should always be in the same place, position of the CCD, let's use the builder's equation to find this distance from the image (i)
     1 / f = 1 / o + 1 / i
Where f is the focal length and "o, i" are the distances to the object and image, respectively
     1 / i = 1 / f - 1 / o
Let's reduce the magnitudes to the SI system
     f = 50 mm = 0.050 m
     o = 5.0 m
 Â
Let's calculate
    1 / i = 1 / 0.050 - 1 / 5.0 = 20- 0.2 = 19.8
     i = 0.020 m
Now the object is 60 cm, rotates the lens and has a new focal length
    o₂ = 60 cm = 0.60 m
    1 / f = 1 / 0.60 + 1 / 0.020 = 1.66 + 50 = 51.66
    f₂ = 0.019 m