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A saline solution contains 0.770 gg of NaClNaCl (molar mass = 58.55 g/molg/mol) in 133 mLmL of solution. Calculate the concentration of NaClNaCl in this solution, in units of molarity.

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Answer:

0.104 M

Explanation:

A saline solution contains 0.770 g of NaCl (molar mass = 58.55 g/mol) in 133 mL.

The molar mass of the solute (NaCl) is 58.55 g/mol. The moles corresponding to 0.770 g are:

0.770 g × (1 mol/55.85 g) = 0.0138 mol

The volume of solution is 133 mL. In liters,

133 mL × (1 L/1000 mL) = 0.133 L

The molarity of NaCl is:

M = moles of solute / liters of solution

M = 0.0138 mol / 0.133 L

M = 0.104 M

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