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08-02-2020
Physics

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A flute player hears four beats per second when she compares her note to an 880 Hz tuning fork (note A). She can match the frequency of the tuning fork by pulling out the "tuning joint" to lengthen her flute slightly. What was her initial frequency?

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Toluene266 Toluene266

08-02-2020

Answer:

884Hz

Explanation:

Beats is the absolute difference between two frequencies therefore

Beats = f1-f2

4=f1-880

F1=880+4

F1=884Hz

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