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A 0.49-kg cord is stretched between two supports,7.3m apart. When one support is struck by a hammer, a transverse wave travels down the cord and reaches the other support in 0.83s .

What is the tension in the cord? (Express your answer to two significant figures and include the appropriate units.)

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Olajidey

Answer:

T= 5.18N

Explanation:

u = mass of chord / length of chord

u = 0.49/ 7.3

u = 0.067 kg/m

Velocity of sound waves (v) =length of chord / time taken for wave to travel

v = 7.3 / 0.83 = 8.795m/s

Tension is calculated below using the formula

T = vĀ² * u

T = (8.795)Ā² x 0.067

T= 5.18N

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