Answer:
The horizontal distance the football will travel is 1.8 m
Explanation:
Given;
vertical velocity Vy = 18 m/s
horizontal velocity Vx = 15 m/s
vertical distance traveled by the football = 1 m
To determine the horizontal distance traveled by the football, after been kicked 1 m above the ground, we apply equation of motion to determine the time spent by the football in the air before hitting the ground.
[tex]y = v_y t+ \frac{1}{2}gt^2 \\\\1 = 18t+4.9t^2\\\\4.9t^2 +8t-1 =0\\\\t = 0.12 s[/tex]
Horizontal distance, [tex]X = v_xt[/tex]
X = 15*0.12 = 1.8 m
Therefore, the horizontal distance the football will travel is 1.8 m
