Answer:
Correct answer is E/4.
Explanation:ρ
by the formula of [tex]R=\frac{\rho L}{A}[/tex]
Now, [tex]R_{1} = \frac{\rho L}{\pi b^{2}} \\ R_{2} = \frac{\rho L}{4\pi b^{2}}[/tex]
and, [tex]R_{1}=4R_{2}[/tex]
The wires are connected in series so the current will be same. So, by the [tex]V=iR[/tex] formula
[tex]V_{1}=4{V_{2}[/tex]
similarly,
[tex]E_{1}=4E_{2}\\E=4E_{2}\\E_{2}=\frac{E}{4}[/tex]
