Answer:
q = 0.0003649123 m²/s = (3.65 × 10⁻⁴) m²/s
Explanation:
For laminar flow between two parallel horizontal plates, the volumetric flow per metre of width is given as
q = (2h³/3μ) (ΔP/L)
h = hydraulic depth = 4mm/2 = 2mm = 0.002 m
μ = viscosity of oil (SAE 30) at 15.6°C = 0.38 Pa.s
(ΔP/L) = 26 KPa/m = 26000 Pa/m
q = (2h³/3μ) (ΔP/L)
q = (26000) × (2(0.002³)/(3×0.38))
q = 0.0003649123 m²/s = (3.65 × 10⁻⁴) m²/s
Answer:
Volume Rate = 3.65 x 10^(-4) m²/s
Explanation:
This is a laminar flow and the formula for the volume rate of flow is given as;
q = ((2h³)/3μ) (ΔP/L)
Where;
h is hydraulic depth
μ is viscosity of oil (SAE 30) at 15.6°
(ΔP/L) is the pressure drop per unit length.
Now, distance between plates is 4mm and h = d/2 = 4/2 = 2mm or 0.002 m
μ is traced out from the graph i attached below and and it's approximately 0.38 Pa.s
(ΔP/L) = 26 KPa/m = 26000 Pa/m
So q = ((2 x 0.002³)/(3 x 0.38))(26,000) = 3.65 x 10^(-4) m²/s
