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What is the output of the following code?

import javafx.beans.property.IntegerProperty;
import javafx.beans.property.SimpleIntegerProperty;

public class Test {
public static void main(String[] args) {
IntegerProperty d1 = new SimpleIntegerProperty(1);
IntegerProperty d2 = new SimpleIntegerProperty(2);
d1.bind(d2);
System.out.print("d1 is " + d1.getValue()
+ " and d2 is " + d2.getValue());
d2.setValue(3);
System.out.println(", d1 is " + d1.getValue()
+ " and d2 is " + d2.getValue());
}
}

a. d1 is 2 and d2 is 2, d1 is 2 and d2 is 3
b. d1 is 1 and d2 is 2, d1 is 3 and d2 is 3
c. d1 is 1 and d2 is 2, d1 is 1 and d2 is 3
d. d1 is 2 and d2 is 2, d1 is 3 and d2 is 3

Respuesta :

asarwar

Answer:

The explanation of this question is given below in explanation section. However the correct option to this question is D.

Explanation:

The code and its explanation is given below:

import javafx.beans.property.IntegerProperty;

import javafx.beans.property.SimpleIntegerProperty;

public class Test {

public static void main(String[] args) {

IntegerProperty d1 = new SimpleIntegerProperty(1);

IntegerProperty d2 = new SimpleIntegerProperty(2);

d1.bind(d2);

System.out.print("d1 is " + d1.getValue()

+ " and d2 is " + d2.getValue());

d2.setValue(3);

System.out.println(", d1 is " + d1.getValue()

+ " and d2 is " + d2.getValue());

}

}

The output of this code is :

d1 is 2 and d2 is 2, d1 is 3 and d2 is 3

The value of d1 is 1 and d2 is 2. After the method d1.bind(). The value of d1 and d2 become 2 and after calling the method d2.setvalue(3) change the value of d1 and d2 to 3.    

 

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