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If a gas in a closed container is pressurized from 14.0 atm to 17.0 atm and its original temperature was 30oC, what would the final temperature of the gas be

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osagieosazeme72

Answer:

367.93K

Explanation:

P1= 14atm

P2= 17atm

T1= 30oC = 273+30= 303k

T2= ??

Using Gay Lussac law

P1/T1 = P2/T2

14/303= 17/x

X= 367.93K

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