Answer:
x = 600 m
y = 1200 m
Amax = 720000  m²
Step-by-step explanation:
Let call x the smaller side of the rectangular plot and y the largest ( we assume we have one y side bounded by a river: Then
A(p) Â Area of the plot x*y
A(p) = x*y
And perimeter of the plot ( to be fenced ) is:
P(p)  = 2*x + y = 2400   ⇒  y  = 2400 - 2*x
Area of rectangular plot as function of x:
A(x) = x * ( 2400 - 2x )
Taking derivatives on both sides of the equation
A´(x) = ( 2400 - 2x ) + (-2) *x   ⇒  A´(x) = ( 2400 - 2x ) - 2x
A´(x) = 0    ⇒  2400 - 4x = 0   ⇒  4x  = 2400 Â
x = 600 m
And y = Â 2400 - 2*x
y = 2400 - 1200
y = 1200 m
And the largest enclosed area is  Amax = 1200*600
Amax = 720000 m²