We are given with the points A (6, -2), B (1, 3), C (5, 5). Using the distance formula, the distance is AB is 5 sq.rt of 2, BC equal to 2 sq.rt of 5 and AC equal to 5 sq rt of 2. Hence this is an isosceles triangle. Through Heron's Formula, the area is equal to D. 15 square units.
