Answer:
Magnitude of the force is 4350N
Explanation:
As the woman accelerates at a distance of 22 m to go from rest to 62.5 m / s, we can use the kinematics to find the acceleration
v² = v₀² + 2 a x
vâ‚€ = 0
a = v² / 2x
 a = 62.5²/(2 × 22)
 a = 88.78m/s²
the time you need to get this speed
   v = v₀ + a t
   t = v / a
   t = 62.5 / 88.78
   t = 0.704s
Let's caculate the magnitude of the force
F = ma
= 49 × 88.78
= 4350.22
≅ 4350N
Magnitude of the force is 4350N
   t = 1,025 s
   a = 55.43 m / s²
