Respuesta :
Answer:
The cost of the candy is
$5 for strawberry taffy and
$4 for banana taffy
Step-by-step explanation:
Here we have
Let the strawberry taffy be = S and
the banana taffy = B
The system of equation becomes
4·S + 6·B = $44......................(1)
2·S + 5·B =$30.......................(2)
To solve the equations, we multiply equation (2) by 2 to get
2×(2·S + 5·B) =$30. × 2
4·S +10·B = $60.......................(3)
We subtract equation (1) from equation (3) to get
(4·S +10·B)-(4·S + 6·B) = $60 - $44
4·B = $16 or B = $16/4 = $4
Therefore, from equation (2) we have
2·S + 5×$4 =$30 or
2·S = $30 - $20 = $10
S = $10/2 = $5
The candy costs
Strawberry taffy = $5 and
Banana taffy = $4
Answer:
Each pound of strawberry taffy and banana taffy costs $5 and $4 respectively
Step-by-step explanation:
Lets assume the price of one pound of strawberry taffy to be x
And
The price of one pound of banana taffy to be y
If 4 pounds of strawberry taffy and 6 pounds of banana taffy costs $44
And
2 pounds of strawberry taffy and 5 pounds of banana taffy costs $30.
The above will lead to a simultaneous equation that looks like this
4x + 6y = 44
From the first equation, we can divide through by 2 and we get
2x + 3y = 22_______equation 1
2x + 5y = 30_______ equation 2
From equation 1,we make x the subject of the formula and we get
X = (22 - 3y)/2
Apply the above in equation 2 and we have
2[(22 - 3y)/2] + 5y = 30
We expand the above equation
(44 - 6y)/2 + 5y = 30
(44 - 6y + 10y)/2 = 30
44 - 6y + 10y = 60
4y = 16
Y= $4(price of a pound of banana taffy)
Now substitute y = 4 in equation 1 and we have
2x + 3(4) = 22
2x + 12 = 22
X = 10/2
X = $5(price of each pound of strawberry taffy)
