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Consider a mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 0.09 L. If the combustion of this mixture releases 900. Jof energy, to what volume will the gases expand against a constant pressure of 670. torr if all the energy of combustion is converted into work to push back the piston? (1 atm = 760 torr, 1 L atm = 101.325 J) a. 10.00 L b. 10.17 L c. 1.47 L d. 1.34L

Respuesta :

Answer: 10.17 L volume is required for the gases to expand against a constant pressure of 670.

Explanation:

The given data is as follows.

          [tex]V_{i}[/tex] = 0.09 L,      P = 670 torr

As,  W = 900 J       (given)

so,       = [tex]\frac{900}{101.325 atm L}[/tex]

           = 8.882 atm L

Now, we will change pressure into atm as follows.

            P = 670 torr

               = [tex]\frac{670}{760}[/tex] atm

               = 0.8816 atm

Therefore, we will calculate the final volume as follows.

          W = [tex]P(V_{f} - V_{i})[/tex]

    8.882 = [tex]0.8816 \times (V_{f} - 0.09)[/tex]

        [tex]V_{f} - 0.09[/tex] = 10.08

           [tex]V_{f}[/tex] = 10.17 L

Thus, we can conclude that 10.17 L volume is required for the gases to expand against a constant pressure of 670.

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